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$$3x^4-4x^5-3x+2 = 0$$
Answer
$$ \begin{matrix}x_1 = 0.68563 & x_2 = 0.67813+0.6352i & x_3 = 0.67813-0.6352i \\[1 em] x_4 = -0.64595+0.65378i & x_5 = -0.64595-0.65378i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x^4-4x^5-3x+2 &= 0&& \text{simplify left side} \\[1 em]-4x^5+3x^4-3x+2 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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Polynomial Equations Solver