$$3x(x-2)-4x(x+1) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -10 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x(x-2)-4x(x+1) &= 0&& \text{simplify left side} \\[1 em]3x^2-6x-(4x^2+4x) &= 0&& \\[1 em]3x^2-6x-4x^2-4x &= 0&& \\[1 em]-x^2-10x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ -x^{2}-10x = 0 } $, first we need to factor our $ x $.
$$ -x^{2}-10x = x \left( -x-10 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ -x-10 = 0$.
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