$$3x(4x^2-7+1)+2x^2+3x-2 = 0$$
Answer
$$ \begin{matrix}x_1 = -0.13286 & x_2 = 1.10326 & x_3 = -1.13707 \end{matrix} $$
Explanation
$$ \begin{aligned} 3x(4x^2-7+1)+2x^2+3x-2 &= 0&& \text{simplify left side} \\[1 em]3x(4x^2-6)+2x^2+3x-2 &= 0&& \\[1 em]12x^3-18x+2x^2+3x-2 &= 0&& \\[1 em]12x^3+2x^2-15x-2 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver