$$3g(2g-4) = 0$$
Answer
$$ \begin{matrix}g_1 = 0 & g_2 = 2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3g(2g-4) &= 0&& \text{simplify left side} \\[1 em]6g^2-12g &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 6x^{2}-12x = 0 } $, first we need to factor our $ x $.
$$ 6x^{2}-12x = x \left( 6x-12 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 6x-12 = 0$.
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