$$36a^3-49a = 0$$
Answer
$$ \begin{matrix}a_1 = 0 & a_2 = \dfrac{ 7 }{ 6 } & a_3 = -\dfrac{ 7 }{ 6 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 36x^{3}-49x = 0 } $, first we need to factor our $ x $.
$$ 36x^{3}-49x = x \left( 36x^{2}-49 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 36x^{2}-49 = 0$.
$ 36x^{2}-49 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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