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$$3(x+2)^2 = 144$$
Answer
$$ \begin{matrix}x_1 = -2-4 \sqrt{ 3 } & x_2 = -2+4 \sqrt{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(x+2)^2 &= 144&& \text{simplify left side} \\[1 em]3(x^2+4x+4) &= 144&& \\[1 em]3x^2+12x+12 &= 144&& \text{move all terms to the left hand side } \\[1 em]3x^2+12x+12-144 &= 0&& \text{simplify left side} \\[1 em]3x^2+12x-132 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+12x-132 = 0 $ is a quadratic equation.
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