$$3(3x+9)x+6 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 57 }}{ 6 } & x_2 = -\dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 57 }}{ 6 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(3x+9)x+6 &= 0&& \text{simplify left side} \\[1 em](9x+27)x+6 &= 0&& \\[1 em]9x^2+27x+6 &= 0&& \\[1 em] \end{aligned} $$
$ 9x^{2}+27x+6 = 0 $ is a quadratic equation.
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