$$2y^2+8y+3 = 0$$
Answer
$$ \begin{matrix}y_1 = -2-\dfrac{\sqrt{ 10 }}{ 2 } & y_2 = -2+\dfrac{\sqrt{ 10 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$ 2x^{2}+8x+3 = 0 $ is a quadratic equation.
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