$$2x^7-4x^2+12x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 1.11782+0.57384i & x_3 = 1.11782-0.57384i \\[1 em] x_4 = -1.21726+0.75131i & x_5 = -1.21726-0.75131i & x_6 = 0.09944+1.35918i \\[1 em] x_7 = 0.09944-1.35918i & \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 2x^{7}-4x^{2}+12x = 0 } $, first we need to factor our $ x $.
$$ 2x^{7}-4x^{2}+12x = x \left( 2x^{6}-4x+12 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{6}-4x+12 = 0$.
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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