$$2x^6-12x^5+18x^4 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 2x^{6}-12x^{5}+18x^{4} = 0 } $, first we need to factor our $ x^4 $.
$$ 2x^{6}-12x^{5}+18x^{4} = x^4 \left( 2x^{2}-12x+18 \right) $$$ x = 0 $ is a root of multiplicity $ 4 $.
The remaining roots can be found by solving equation $ 2x^{2}-12x+18 = 0$.
$ 2x^{2}-12x+18 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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