$$2x^3+23x^2+45x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -\dfrac{ 5 }{ 2 } & x_3 = -9 \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 2x^{3}+23x^{2}+45x = 0 } $, first we need to factor our $ x $.
$$ 2x^{3}+23x^{2}+45x = x \left( 2x^{2}+23x+45 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{2}+23x+45 = 0$.
$ 2x^{2}+23x+45 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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