$$2x(x-4)+3(x+5) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 5 }{ 4 }+\dfrac{\sqrt{ 95 }}{ 4 }i & x_2 = \dfrac{ 5 }{ 4 }-\dfrac{\sqrt{ 95 }}{ 4 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x(x-4)+3(x+5) &= 0&& \text{simplify left side} \\[1 em]2x^2-8x+3x+15 &= 0&& \\[1 em]2x^2-5x+15 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-5x+15 = 0 $ is a quadratic equation.
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