$$2x(x+3)(x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 1 & x_3 = -3 \end{matrix} $$
Explanation
$$ \begin{aligned} 2x(x+3)(x-1) &= 0&& \text{simplify left side} \\[1 em]2x(x^2-x+3x-3) &= 0&& \\[1 em]2x(x^2+2x-3) &= 0&& \\[1 em]2x^3+4x^2-6x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 2x^{3}+4x^{2}-6x = 0 } $, first we need to factor our $ x $.
$$ 2x^{3}+4x^{2}-6x = x \left( 2x^{2}+4x-6 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{2}+4x-6 = 0$.
$ 2x^{2}+4x-6 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver