$$2w\cdot3-3w\cdot2-12w+18 = 0$$

$$ \begin{aligned} 2w\cdot3-3w\cdot2-12w+18 &= 0&& \text{simplify left side} \\[1 em]2w\cdot3-3w\cdot2-12w+18 &= 0&& \\[1 em]6w-6w-12w+18 &= 0&& \\[1 em]6w-6w-12w+18 &= 0&& \\[1 em]-12w+18 &= 0&& \text{ move the constants to the right } \\[1 em]-12w &= -18&& \text{ divide both sides by $ -12 $ } \\[1 em]w &= \frac{-18}{-12}&& \\[1 em]w &= \frac{3}{2}&& \\[1 em] \end{aligned} $$

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