$$2v(9v-2) = 0$$
Answer
$$ \begin{matrix}v_1 = 0 & v_2 = \dfrac{ 2 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2v(9v-2) &= 0&& \text{simplify left side} \\[1 em]18v^2-4v &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 18x^{2}-4x = 0 } $, first we need to factor our $ x $.
$$ 18x^{2}-4x = x \left( 18x-4 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 18x-4 = 0$.
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