$$2h^3 = -6h-13h\cdot2$$
Answer
$$ \begin{matrix}h_1 = 0 & h_2 = 4 i & h_3 = -4 i \end{matrix} $$
Explanation
$$ \begin{aligned} 2h^3 &= -6h-13h\cdot2&& \text{simplify right side} \\[1 em]2h^3 &= -6h-26h&& \\[1 em]2h^3 &= -32h&& \text{move all terms to the left hand side } \\[1 em]2h^3+32h &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 2x^{3}+32x = 0 } $, first we need to factor our $ x $.
$$ 2x^{3}+32x = x \left( 2x^{2}+32 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{2}+32 = 0$.
$ 2x^{2}+32 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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