$$2h^3 = -6h-13h^2$$
Answer
$$ \begin{matrix}h_1 = 0 & h_2 = -\dfrac{ 1 }{ 2 } & h_3 = -6 \end{matrix} $$
Explanation
$$ \begin{aligned} 2h^3 &= -6h-13h^2&& \text{simplify right side} \\[1 em]2h^3 &= -13h^2-6h&& \text{move all terms to the left hand side } \\[1 em]2h^3+13h^2+6h &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 2x^{3}+13x^{2}+6x = 0 } $, first we need to factor our $ x $.
$$ 2x^{3}+13x^{2}+6x = x \left( 2x^{2}+13x+6 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 2x^{2}+13x+6 = 0$.
$ 2x^{2}+13x+6 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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