$$25x^4-4x^2 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 2 }{ 5 } & x_3 = -\dfrac{ 2 }{ 5 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 25x^{4}-4x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ 25x^{4}-4x^{2} = x^2 \left( 25x^{2}-4 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The remaining roots can be found by solving equation $ 25x^{2}-4 = 0$.
$ 25x^{2}-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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