$$23w^2+42 = 5w^2-14$$
Answer
$$ \begin{matrix}w_1 = \dfrac{ 2 \sqrt{ 7}}{ 3 } i & w_2 = -2 \dfrac{\sqrt{ 7 }}{ 3 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 23w^2+42 &= 5w^2-14&& \text{move all terms to the left hand side } \\[1 em]23w^2+42-5w^2+14 &= 0&& \text{simplify left side} \\[1 em]18w^2+56 &= 0&& \\[1 em] \end{aligned} $$
$ 18x^{2}+56 = 0 $ is a quadratic equation.
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