$$2^2-3x+8 = 10$$
Answer
$$ x = \frac{2}{3} $$
Explanation
$$ \begin{aligned} 2^2-3x+8 &= 10&& \text{simplify left side} \\[1 em]4-3x+8 &= 10&& \\[1 em]-3x+12 &= 10&& \text{ move 12 to the right } \\[1 em]-3x &= 10-12&& \\[1 em]-3x &= -2&& \text{ divide both sides by $ -3 $ } \\[1 em]x &= \frac{-2}{-3}&& \\[1 em]x &= \frac{2}{3}&& \\[1 em] \end{aligned} $$
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