$$ \begin{aligned} 2\cdot(7+3)-3\cdot(5-1) &= 0&& \text{simplify left side} \\[1 em]2\cdot10-3\cdot4 &= 0&& \\[1 em]20-12 &= 0&& \\[1 em]8 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 8 = 0 } $ is FALSE, we conclude that the equation has no solution.
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