$$18s^3+240s^2+800s = 0$$
Answer
$$ \begin{matrix}s_1 = 0 & s_2 = -\dfrac{ 20 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ 18x^{3}+240x^{2}+800x = 0 } $, first we need to factor our $ x $.
$$ 18x^{3}+240x^{2}+800x = x \left( 18x^{2}+240x+800 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ 18x^{2}+240x+800 = 0$.
$ 18x^{2}+240x+800 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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