$$17y^2-34 = 18y^2+11$$
Answer
$$ \begin{matrix}y_1 = 3 \sqrt{ 5 } i & y_2 = -3 \sqrt{ 5 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 17y^2-34 &= 18y^2+11&& \text{move all terms to the left hand side } \\[1 em]17y^2-34-18y^2-11 &= 0&& \text{simplify left side} \\[1 em]-y^2-45 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}-45 = 0 $ is a quadratic equation.
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