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$$120x^{21}-128x^{20}-100x+108 = 0$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = -0.99125 & x_3 = 1.06224 \\[1 em] x_4 = 0.58218+0.80232i & x_5 = 0.58218-0.80232i & x_6 = -0.58277+0.80184i \\[1 em] x_7 = -0.58277-0.80184i & x_8 = -0.30653+0.94267i & x_9 = -0.30653-0.94267i \\[1 em] x_10 = 0.80148+0.58346i & x_11 = 0.80148-0.58346i & x_12 = 0.30592+0.94288i \\[1 em] x_13 = 0.30592-0.94288i & x_14 = -0.80199+0.58256i & x_15 = -0.80199-0.58256i \\[1 em] x_16 = -0.00031+0.99126i & x_17 = -0.00031-0.99126i & x_18 = 0.9426+0.30818i \\[1 em] x_19 = 0.9426-0.30818i & x_20 = -0.94275+0.30627i & x_21 = -0.94275-0.30627i \end{matrix} $$
Explanation
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