$$10-3x^2+x^5+4x^3 = 0$$
Answer
$$ \begin{matrix}x_1 = -1.07973 & x_2 = 0.98999+0.90461i & x_3 = 0.98999-0.90461i \\[1 em] x_4 = -0.45013+2.22425i & x_5 = -0.45013-2.22425i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 10-3x^2+x^5+4x^3 &= 0&& \text{simplify left side} \\[1 em]x^5+4x^3-3x^2+10 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
This page was created using
Polynomial Equations Solver