$$\frac{1}{3}x^3-\frac{9}{2}x^2+6x+7 = 0$$
Answer
$$ \begin{matrix}x_1 = -0.73702 & x_2 = 2.40893 & x_3 = 11.8281 \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{1}{3}x^3-\frac{9}{2}x^2+6x+7 &= 0&& \text{multiply ALL terms by } \color{blue}{ 6 }. \\[1 em]6 \cdot \frac{1}{3}x^3-6\frac{9}{2}x^2+6\cdot6x+6\cdot7 &= 6\cdot0&& \text{cancel out the denominators} \\[1 em]2x^3-27x^2+36x+42 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
This page was created using
Polynomial Equations Solver