$$-8v+2 = -3v^2$$
Answer
$$ \begin{matrix}v_1 = \dfrac{ 4 }{ 3 }-\dfrac{\sqrt{ 10 }}{ 3 } & v_2 = \dfrac{ 4 }{ 3 }+\dfrac{\sqrt{ 10 }}{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -8v+2 &= -3v^2&& \text{move all terms to the left hand side } \\[1 em]-8v+2+3v^2 &= 0&& \text{simplify left side} \\[1 em]3v^2-8v+2 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-8x+2 = 0 $ is a quadratic equation.
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