$$-3x(4x-2) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 1 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -3x(4x-2) &= 0&& \text{simplify left side} \\[1 em]-(12x^2-6x) &= 0&& \\[1 em]-12x^2+6x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ -12x^{2}+6x = 0 } $, first we need to factor our $ x $.
$$ -12x^{2}+6x = x \left( -12x+6 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ -12x+6 = 0$.
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