$$-3+3x^2+6x^3+9x^4 = 0$$
Answer
$$ \begin{matrix}x_1 = 0.56774 & x_2 = -0.83695 & x_3 = -0.19873+0.81364i \\[1 em] x_4 = -0.19873-0.81364i & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -3+3x^2+6x^3+9x^4 &= 0&& \text{simplify left side} \\[1 em]9x^4+6x^3+3x^2-3 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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