$$-3(x-2)(7x+1) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 7 } & x_2 = 2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -3(x-2)(7x+1) &= 0&& \text{simplify left side} \\[1 em]-(3x-6)(7x+1) &= 0&& \\[1 em]-(21x^2+3x-42x-6) &= 0&& \\[1 em]-(21x^2-39x-6) &= 0&& \\[1 em]-21x^2+39x+6 &= 0&& \\[1 em] \end{aligned} $$
$ -21x^{2}+39x+6 = 0 $ is a quadratic equation.
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