$$-2y^3+y^2-3y+4 = y\cdot3$$
Answer
$$ \begin{matrix}y_1 = 0.6463 & y_2 = -0.07315+1.75761i & y_3 = -0.07315-1.75761i \end{matrix} $$
Explanation
$$ \begin{aligned} -2y^3+y^2-3y+4 &= y\cdot3&& \text{move all terms to the left hand side } \\[1 em]-2y^3+y^2-3y+4-3y &= 0&& \text{simplify left side} \\[1 em]-2y^3+y^2-6y+4 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using qubic formulas.
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