$$-x^3+5x^2+36x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -4 & x_3 = 9 \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ -x^{3}+5x^{2}+36x = 0 } $, first we need to factor our $ x $.
$$ -x^{3}+5x^{2}+36x = x \left( -x^{2}+5x+36 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ -x^{2}+5x+36 = 0$.
$ -x^{2}+5x+36 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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