$$-x^3+11x^2+110x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 11 }{ 2 }-\dfrac{\sqrt{ 561 }}{ 2 } & x_3 = \dfrac{ 11 }{ 2 }+\dfrac{\sqrt{ 561 }}{ 2 } \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ -x^{3}+11x^{2}+110x = 0 } $, first we need to factor our $ x $.
$$ -x^{3}+11x^{2}+110x = x \left( -x^{2}+11x+110 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ -x^{2}+11x+110 = 0$.
$ -x^{2}+11x+110 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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