In order to solve $ \color{blue}{ -x^{3}+10x^{2}-9x = 0 } $, first we need to factor our $ x $.
$$ -x^{3}+10x^{2}-9x = x \left( -x^{2}+10x-9 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ -x^{2}+10x-9 = 0$.
$ -x^{2}+10x-9 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.