$$-x^3-3x^2+10x = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 2 & x_3 = -5 \end{matrix} $$
Explanation
In order to solve $ \color{blue}{ -x^{3}-3x^{2}+10x = 0 } $, first we need to factor our $ x $.
$$ -x^{3}-3x^{2}+10x = x \left( -x^{2}-3x+10 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The remaining roots can be found by solving equation $ -x^{2}-3x+10 = 0$.
$ -x^{2}-3x+10 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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