$$-\frac{17}{25}x^2+\frac{96}{5}x-112 = 0$$
Answer
$$ \begin{matrix}x_1 = 20 & x_2 = \dfrac{ 140 }{ 17 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -\frac{17}{25}x^2+\frac{96}{5}x-112 &= 0&& \text{multiply ALL terms by } \color{blue}{ 25 }. \\[1 em]-25 \cdot \frac{17}{25}x^2+25\frac{96}{5}x-25\cdot112 &= 25\cdot0&& \text{cancel out the denominators} \\[1 em]-17x^2+480x-2800 &= 0&& \\[1 em] \end{aligned} $$
$ -17x^{2}+480x-2800 = 0 $ is a quadratic equation.
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