$$-\frac{1}{36}x^2+14x+67 = 393$$
Answer
$$ \begin{matrix}x_1 = 252-6 \sqrt{ 1438 } & x_2 = 252+6 \sqrt{ 1438 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -\frac{1}{36}x^2+14x+67 &= 393&& \text{multiply ALL terms by } \color{blue}{ 36 }. \\[1 em]-36 \cdot \frac{1}{36}x^2+36\cdot14x+36\cdot67 &= 36\cdot393&& \text{cancel out the denominators} \\[1 em]-x^2+504x+2412 &= 14148&& \text{move all terms to the left hand side } \\[1 em]-x^2+504x+2412-14148 &= 0&& \text{simplify left side} \\[1 em]-x^2+504x-11736 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+504x-11736 = 0 $ is a quadratic equation.
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