$$\frac{5x^2+8x+3}{x+1} = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -\dfrac{ 3 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{5x^2+8x+3}{x+1} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+1 }. \\[1 em](x+1)\frac{5x^2+8x+3}{x+1} &= (x+1)\cdot0&& \text{cancel out the denominators} \\[1 em]5x^2+8x+3 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}+8x+3 = 0 $ is a quadratic equation.
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