$$(y+2)(y-6) = 0$$
Answer
$$ \begin{matrix}y_1 = -2 & y_2 = 6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (y+2)(y-6) &= 0&& \text{simplify left side} \\[1 em]y^2-6y+2y-12 &= 0&& \\[1 em]y^2-4y-12 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-4x-12 = 0 $ is a quadratic equation.
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