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$$(x+5)(3x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 4 }{ 3 } & x_2 = -5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+5)(3x-4) &= 0&& \text{simplify left side} \\[1 em]3x^2-4x+15x-20 &= 0&& \\[1 em]3x^2+11x-20 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+11x-20 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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