$$(x+4)(x-18) = 0$$
Answer
$$ \begin{matrix}x_1 = -4 & x_2 = 18 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+4)(x-18) &= 0&& \text{simplify left side} \\[1 em]x^2-18x+4x-72 &= 0&& \\[1 em]x^2-14x-72 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-14x-72 = 0 $ is a quadratic equation.
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