$$(x+2)(x+5) = -2$$
Answer
$$ \begin{matrix}x_1 = -3 & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+2)(x+5) &= -2&& \text{simplify left side} \\[1 em]x^2+5x+2x+10 &= -2&& \\[1 em]x^2+7x+10 &= -2&& \text{move all terms to the left hand side } \\[1 em]x^2+7x+10+2 &= 0&& \text{simplify left side} \\[1 em]x^2+7x+12 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+7x+12 = 0 $ is a quadratic equation.
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