$$(x+2)\cdot(4-x) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+2)\cdot(4-x) &= 0&& \text{simplify left side} \\[1 em]4x-x^2+8-2x &= 0&& \\[1 em]-x^2+2x+8 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+2x+8 = 0 $ is a quadratic equation.
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