$$(x+1)^2+14(x+1)+45 = 0$$
Answer
$$ \begin{matrix}x_1 = -6 & x_2 = -10 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+1)^2+14(x+1)+45 &= 0&& \text{simplify left side} \\[1 em]x^2+2x+1+14(x+1)+45 &= 0&& \\[1 em]x^2+2x+1+14x+14+45 &= 0&& \\[1 em]x^2+16x+15+45 &= 0&& \\[1 em]x^2+16x+60 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+16x+60 = 0 $ is a quadratic equation.
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