$$(x+1)(x+8) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+1)(x+8) &= 0&& \text{simplify left side} \\[1 em]x^2+8x+x+8 &= 0&& \\[1 em]x^2+9x+8 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+9x+8 = 0 $ is a quadratic equation.
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