$$(x+1)(3x-2) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = \dfrac{ 2 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+1)(3x-2) &= 0&& \text{simplify left side} \\[1 em]3x^2-2x+3x-2 &= 0&& \\[1 em]3x^2+x-2 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+x-2 = 0 $ is a quadratic equation.
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