$$(x-7)(x-5) = 0$$
Answer
$$ \begin{matrix}x_1 = 5 & x_2 = 7 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-7)(x-5) &= 0&& \text{simplify left side} \\[1 em]x^2-5x-7x+35 &= 0&& \\[1 em]x^2-12x+35 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-12x+35 = 0 $ is a quadratic equation.
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