$$(x-4)^2+2 = 0$$
Answer
$$ \begin{matrix}x_1 = 4+\sqrt{ 2 }i & x_2 = 4-\sqrt{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-4)^2+2 &= 0&& \text{simplify left side} \\[1 em]x^2-8x+16+2 &= 0&& \\[1 em]x^2-8x+18 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-8x+18 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Polynomial Equations Solver