$$(x-3)(x+18) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -18 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)(x+18) &= 0&& \text{simplify left side} \\[1 em]x^2+18x-3x-54 &= 0&& \\[1 em]x^2+15x-54 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+15x-54 = 0 $ is a quadratic equation.
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