$$(x-3)(5x+7) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -\dfrac{ 7 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)(5x+7) &= 0&& \text{simplify left side} \\[1 em]5x^2+7x-15x-21 &= 0&& \\[1 em]5x^2-8x-21 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}-8x-21 = 0 $ is a quadratic equation.
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